발표자: 김준호(Lunit)
발표일: 2018.1.
의료 AI 관련 중, nodule detection 문제에 대해 다뤄보고자 합니다.
의료 AI에서는 어떠한 방식으로 classication을 하고, preprocessing은 어떤식으로 진행되는지 LUNA16이라는 의료 challenge에 이용되는 데이터를 가지고 발표를 진행해보고자 합니다.
이후, 이 데이터를 이용해서 최근 2017 MICCAI (의료 영상학회에서는 높은 수준의 학회)에서 발표된 "curriculum adaptive sampling for extreme data imbalance"를 실제 구현해서 적용해보고 이 때 발생할 수 있는 문제를 어떤식으로 해결할 수 있는지에 대한 tip도 제공할 예정입니다. (Python multi-processing data load, input-pipeline)
위 논문을 선정한 이유는, 단순한 classification이 아닌, nodule이 있는 위치도 정확하게 catch하는 논문 중, performance가 상당히 높기 때문입니다.
Курс "Программирование на Java". Лекция 07 "Бонус - Головоломки".
Java Puzzlers. Синхронизация и многопоточность. Примитивы. Объекты и классы. Исключения и финализация.
МФТИ, 2016 год. Лектор - Лаврентьев Федор Сергеевич
발표자: 김준호(Lunit)
발표일: 2018.1.
의료 AI 관련 중, nodule detection 문제에 대해 다뤄보고자 합니다.
의료 AI에서는 어떠한 방식으로 classication을 하고, preprocessing은 어떤식으로 진행되는지 LUNA16이라는 의료 challenge에 이용되는 데이터를 가지고 발표를 진행해보고자 합니다.
이후, 이 데이터를 이용해서 최근 2017 MICCAI (의료 영상학회에서는 높은 수준의 학회)에서 발표된 "curriculum adaptive sampling for extreme data imbalance"를 실제 구현해서 적용해보고 이 때 발생할 수 있는 문제를 어떤식으로 해결할 수 있는지에 대한 tip도 제공할 예정입니다. (Python multi-processing data load, input-pipeline)
위 논문을 선정한 이유는, 단순한 classification이 아닌, nodule이 있는 위치도 정확하게 catch하는 논문 중, performance가 상당히 높기 때문입니다.
Курс "Программирование на Java". Лекция 07 "Бонус - Головоломки".
Java Puzzlers. Синхронизация и многопоточность. Примитивы. Объекты и классы. Исключения и финализация.
МФТИ, 2016 год. Лектор - Лаврентьев Федор Сергеевич
Курс "Программирование на Java". Лекция 04 "Обобщения и лямбды".
Массивы. Механизм обобщений (Generics), надтипы и подтипы (supertypes and subtypes). Лямбда-функции, функциональные интерфейсы. Пакет java.util.collections, списки (Lists), множества (Sets), словари (Maps), итераторы (Iterators and Iterables). Иерархия коллекций.
МФТИ, 2016 год. Лектор - Лаврентьев Федор Сергеевич
Characteristics of Java and basic programming constructs like Data types, Variables, Operators, Control Statements, Arrays are discussed with relevant examples
Курс "Программирование на Java". Лекция 04 "Обобщения и лямбды".
Массивы. Механизм обобщений (Generics), надтипы и подтипы (supertypes and subtypes). Лямбда-функции, функциональные интерфейсы. Пакет java.util.collections, списки (Lists), множества (Sets), словари (Maps), итераторы (Iterators and Iterables). Иерархия коллекций.
МФТИ, 2016 год. Лектор - Лаврентьев Федор Сергеевич
Characteristics of Java and basic programming constructs like Data types, Variables, Operators, Control Statements, Arrays are discussed with relevant examples
For this project, write a program that stores integers in a binary.docxbudbarber38650
For this project, write a program that stores integers in a binary search tree.
The tree should use the BTNode class which is provided.
Write a test program that generates 20 random numbers in the range of -50 to 50 to build the tree and then uses preorderPrint,
inorderPrint, and postOrderPrint to display the contents of the tree.
To get an A implement a new method for the BTNode class which creates a Java vector class to contain
the data from all the nodes in the tree. The specification for this method is provided in the BTNode file.
Details about the Java vector class are provided in Appendix D, although the only vector method you'll use is addElement.
Also specify and implement in-order and post-order traversals and answer the question which of the
three new methods creates a vector with the entries sorted from smallest to largest?
Your test program should display the vectors created by your new methods rather than the print methods of BTNode.
// File: BTNode.java from the package edu.colorado.nodes
// Complete documentation is available from the BTNode link in:
// http://www.cs.colorado.edu/~main/docs/
package BTNode;
import java.util.Vector;
/******************************************************************************
* A <CODE>BTNode<<E></CODE> provides a node for a binary tree. Each node
* contains a piece of data (which is a reference to an E object) and references
* to a left and right child. The references to children may be null to indicate
* that there is no child. The reference stored in a node can also be null.
*
* <dl><dt><b>Limitations:</b> <dd>
* Beyond <CODE>Int.MAX_VALUE</CODE> elements, <CODE>treeSize</CODE>, is
* wrong.
*
* <dt><b>Java Source Code for this class:</b><dd>
* <A HREF="../../../../edu/colorado/nodes/BTNode.java">
* http://www.cs.colorado.edu/~main/edu/colorado/nodes/BTNode.java </A>
*
* @author Michael Main
* <A HREF="mailto:[email protected]"> ([email protected]) </A>
*
* @version
* Jul 22, 2005
******************************************************************************/
public class BTNode<E>
{
// Invariant of the BTNode<E> class:
// 1. Each node has one reference to an E Object, stored in the instance
// variable data.
// 2. The instance variables left and right are references to the node's
// left and right children.
private E data;
private BTNode<E> left, right;
/**
* Initialize a <CODE>BTNode</CODE> with a specified initial data and links
* children. Note that a child link may be the null reference,
* which indicates that the new node does not have that child.
* @param <CODE>initialData</CODE>
* the initial data of this new node
* @param <CODE>initialLeft</CODE>
* a reference to the left child of this new node--this reference may be null
* to indicate that there is no node after this new node.
* @param <CODE>initialRight</CODE>
.
Please read the comment ins codeExpressionTree.java-------------.pdfshanki7
Please read the comment ins code
ExpressionTree.java
----------------------------------
/**
* This is the class for Expression Tree.
* Used to create Expression Tree and Evaluate it
*/
/**
* Following logic is used to construct a Tree
* Here we use stack for Preparing Tree
* Loop through given Expression String
* If Character is Operand , Create node and push to stack
* If Character is Operator then
* 1)Create Node for Operator
* 2)Pop 2 nodes from Stack and Made
* OpretorNode--> left == first node pop
* OpretorNode--> right == second node pop
* At the end of creation of Expression Tree, Stack have only one node , which is root of
Expression tree
*/
/** Class ExpressionTree **/
class ExpressionTree
{
/** class TreeNode
* Stored Character ==> Digit(0..9) or a Operator +,-,*,/
* Left Node and Right Node
*
* **/
class TreeNode
{
char data;
TreeNode left, right;
/** constructor **/
public TreeNode(char data)
{
this.data = data;
this.left = null;
this.right = null;
}
}
/** class StackNode **/
class StackNode
{
TreeNode treeNode;
StackNode next;
/** constructor **/
public StackNode(TreeNode treeNode)
{
this.treeNode = treeNode;
next = null;
}
}
private static StackNode top;
/** constructor
* Constructor takes input string like \"+-+7*935*82*625\"
* Input should be in Prefix notation
* **/
public ExpressionTree(String expression)
{
top = null;
//Call Method for prepare expression tree
buildTree(expression);
}
/** function to clear tree **/
public void clear()
{
top = null;
}
/** function to push a node **/
private void push(TreeNode ptr)
{
if (top == null)
top = new StackNode(ptr);
else
{
StackNode nptr = new StackNode(ptr);
nptr.next = top;
top = nptr;
}
}
/** function to pop a node
* When it find operator pop 2 elements from Stack
*
* **/
private TreeNode pop()
{
if (top == null)
throw new RuntimeException(\"Underflow\");
else
{
TreeNode ptr = top.treeNode;
top = top.next;
return ptr;
}
}
/** function to get top node **/
private TreeNode peek()
{
return top.treeNode;
}
/** function to insert character **/
private void insert(char val)
{
try
{
//If Operand , Create node and push to Stack
if (isDigit(val))
{
TreeNode nptr = new TreeNode(val);
push(nptr);
}
//If Operator , Create node and popup 2 elements and make them its right and left
else if (isOperator(val))
{
TreeNode nptr = new TreeNode(val);
nptr.left = pop();
nptr.right = pop();
push(nptr);
}
}
catch (Exception e)
{
System.out.println(\"Invalid Expression\");
}
}
/** function to check if digit **/
private boolean isDigit(char ch)
{
return ch >= \'0\' && ch <= \'9\';
}
/** function to check if operator **/
private boolean isOperator(char ch)
{
return ch == \'+\' || ch == \'-\' || ch == \'*\' || ch == \'/\';
}
/** function to convert character to digit **/
private int toDigit(char ch)
{
return ch - \'0\';
}
/** function to build tree from input */
public void buildTree(String eqn)
{
for (int i = eqn.length() - 1; i >= 0; i--)
insert(eqn.charAt(i));
}
/** function to evaluate tree */
public dou.
in this assignment you are asked to write a simple driver program an.pdfmichardsonkhaicarr37
in this assignment you are asked to write a simple driver program and set of functions (maybein
a library) that can be performed on a binary search tree.
Your program should allow user to insert/delete integer values into the binary search tree along
with several other operations on the binary search tree. You can use the code given in slides. But
this time your key will be int! Specifically, your program will ask user to enter a command and
related parameters (if any) in a loop, and then perform the given commands. Here is the list of
commands that your program must implement:
* insert
*find\'
*delete
*list inorder
*list preorder
*list postorder
*list levelorder
* max
* min
* height
*count
* sum
*quit
As always, make sure you release (free) the dynamically allocated memories if you allocate any
memory in your programs. So, before submitting your program, run it with valgrind to see if
there is any memory leakage
//my proggram in C
struct tree_node {
int data;
struct tree_node *left, *right;
}
typedef struct nodeT {
int key;
struct nodeT *left, *right;
} nodeT, *treeT;
int main(){
while (TRUE) {
printf(\"> \");
line = GetLine();
ch = toupper(line[0]);
switch (ch) {
case \'I\': insert(); break;
case \'F\': find(); break;
case \'D\': delete(); break;
case \'LI\': listInorder; break;
case \'LPR\': listPreorder(); break;
case \'LPO\': listPostorder(); break;
case \'MAX\': max(); break;
case \'min\': min(); break;
case \'H\': height(); break;
case \'C\': count(); break;
case \'S\': sum(); break;
case \'Q\': exit(0);
default:printf(\"Illegal command\ \"); break;
}
}
}
nodeT *FindNode(nodeT *t, int key){
while(t !=NULL) {
if (key == t->key) return t;
if (key < t->key) {
t = t->left;
} else {
t = t->right;
}
return NULL;
}
void delete(nodeT **p){
nodeT
*target;
target=*p;
if (target->left==NULL && target->right==NULL) {
*p=NULL;
} else if (target->left == NULL) {
*p=target->right;
} else
if (target->right == NULL) {
*p=target->left;
} else {
/* target has two children, see next slide */
}
free(target);
}
void listInorder(nodeT *T){
if (t != NULL) {
DisplayTree(t->left);
printf(“%d “, t->key);
DisplayTree(t->right);
}
}
void listPreorder(nodeT *t) {
if (t != NULL) {
printf(“%d “, t->key);
DisplayTree(t->left);
DisplayTree(t->right);
}
}
void listPostOrder(nodeT *t){
if (t != NULL) {
DisplayTree(t->left);
DisplayTree(t->right);
printf(“%d “, t->key);
}
}
void intsert(nodeT **tptr, int key){
nodeT*t, *tmp;
t=*tptr;
if (t == NULL) {
tmp=New(nodeT*);
tmp->key = key;
tmp->left=tmp->right=NULL;
*tptr=tmp;
return;
}
if (key < t->key) {
InsertNode
(&t->left, key);
} else {
InsertNode(&t->right, key);
}
}
int height(nodeT *t){
if (t == NULL)
return 0;
else
return (1 + maximumof(
height(t->left),
height(t->right)) );
}
int sum(struct tree_node *p){
if (p == NULL)
return 0;
else
return (p->data +
sum(p->left) +
sum(p->right) );
}
Solution
1. /*
2. * Java Program to Implement Binary Search Tree
3. */
4.
5. import java.util.Scanner;
6.
7. /* Class BSTNode */
8. cl.
To create a node for a binary search tree (BTNode, ) and to create a .pdfbhim1213
To create a node for a binary search tree (BTNode, ) and to create a binary search tree of
comparable objects (Tree BTNode BTNode -data:E -left: BTNode -right: BTNode +BTNode
(newData:E, newLeft: BTNode, newRight: BTNode) +getData():E +getLeft():BTNode
+getRight():BTNode +getRightMostData():E +inOrderPrint():void +removeRightmost():
BTNode +setData(newData:E):void +setLeft(newleft: BTNode):void +setRight(newRight:
BTNode):void needed for remove needed for remove Tree for Lab 7 Tree -root: 8TNode -
numltems:int +Tree() +add(element:E):void +remove(element:E):boolean + remove
+size():int + printTree():void
Solution
//BTNode.java
public class BTNode
{
private E data;
private BTNode left;
private BTNode right;
public BTNode(E newData, BTNode newLeft, BTNode newRight)
{
data = newData;
left = newLeft;
right = newRight;
}//end constructor
/**
* Returns the data
* @return The data
*/
public E getData()
{
return data;
}//end getData
/**
* Returns the left link
* @return the left link
*/
public BTNode getLeft()
{
return left;
}//end getLeft
/**
* Returns the right link
* @return the right link
*/
public BTNode getRight()
{
return right;
}//end getRight
/**
* Prints the tree in order from left to right.
*/
public void inOrderPrint()
{
if (left != null){
left.inOrderPrint();
}//end left
System.out.println(data);
if(right != null){
right.inOrderPrint();
}//end right
}//end inOrderPrint
/**
* Sets the data in the node
* @param newData The new data to be passed
*/
public void setData(E newData)
{
data = newData;
}//end setData
/**
* Sets a new link to left
* @param newLeft the new link to go left
*/
public void setLeft(BTNode newLeft)
{
left = newLeft;
}//end setLeft
/**
* Sets a new link to the right
* @param newRight the new link to the right
*/
public void setRight(BTNode newRight)
{
right = newRight;
}//end setRight
public E getRightMostData()
{
if(right == null){
return data;
} else {
return right.getRightMostData();
}//end right == null if-else
}//end getRightMostData
public BTNode removeRightmost()
{
if (right == null){
return left;
} else {
right = right.removeRightmost();
return this;
}//end if right == null if=-else
}//end removeRightMost
}//end BTNode
=====================================================================
==
//Tree.java
public class Tree>
{
private BTNode root;
private int numItems;
/**
* No-arg constructor
*/
public Tree()
{
root = null;
numItems = 0;
}//end constructor
public void add(E element)
{
if (root == null) {
root = new BTNode(element, null, null);
}else{
BTNode cursor = root;
boolean done = false;
while(!done){
if (element.compareTo(cursor.getData()) <= 0){//cursor.getData().compareTo(element) > 0){
if (cursor.getLeft() == null) {
cursor.setLeft(new BTNode(element,null,null));
done = true;
} else {
cursor = cursor.getLeft();
} //end left is null if-else
}else{
if(cursor.getRight() == null){
cursor.setRight(new BTNode(element, null, null));
done = true;
}else{
cursor = cursor.getRight();
}//end cursor.getRight if-else
}/.
Selection Sort, Insertion Sort, Bubble Sort Main idea: find the smallest element put it in the first position find the next smallest element put it in the second position
Computer notes - Binary Search Tree with Strings ecomputernotes
Notice that the words are sorted in increasing order when we traversed the tree in inorder manner. This should not come as a surprise if you consider how we built the BST. For a given node, values less than the info in the node were all in the left subtree and values greater or equal were in the right.
Taurus Zodiac Sign_ Personality Traits and Sign Dates.pptxmy Pandit
Explore the world of the Taurus zodiac sign. Learn about their stability, determination, and appreciation for beauty. Discover how Taureans' grounded nature and hardworking mindset define their unique personality.
3.0 Project 2_ Developing My Brand Identity Kit.pptxtanyjahb
A personal brand exploration presentation summarizes an individual's unique qualities and goals, covering strengths, values, passions, and target audience. It helps individuals understand what makes them stand out, their desired image, and how they aim to achieve it.
As a business owner in Delaware, staying on top of your tax obligations is paramount, especially with the annual deadline for Delaware Franchise Tax looming on March 1. One such obligation is the annual Delaware Franchise Tax, which serves as a crucial requirement for maintaining your company’s legal standing within the state. While the prospect of handling tax matters may seem daunting, rest assured that the process can be straightforward with the right guidance. In this comprehensive guide, we’ll walk you through the steps of filing your Delaware Franchise Tax and provide insights to help you navigate the process effectively.
Personal Brand Statement:
As an Army veteran dedicated to lifelong learning, I bring a disciplined, strategic mindset to my pursuits. I am constantly expanding my knowledge to innovate and lead effectively. My journey is driven by a commitment to excellence, and to make a meaningful impact in the world.
Attending a job Interview for B1 and B2 Englsih learnersErika906060
It is a sample of an interview for a business english class for pre-intermediate and intermediate english students with emphasis on the speking ability.
Unveiling the Secrets How Does Generative AI Work.pdfSam H
At its core, generative artificial intelligence relies on the concept of generative models, which serve as engines that churn out entirely new data resembling their training data. It is like a sculptor who has studied so many forms found in nature and then uses this knowledge to create sculptures from his imagination that have never been seen before anywhere else. If taken to cyberspace, gans work almost the same way.
[Note: This is a partial preview. To download this presentation, visit:
https://www.oeconsulting.com.sg/training-presentations]
Sustainability has become an increasingly critical topic as the world recognizes the need to protect our planet and its resources for future generations. Sustainability means meeting our current needs without compromising the ability of future generations to meet theirs. It involves long-term planning and consideration of the consequences of our actions. The goal is to create strategies that ensure the long-term viability of People, Planet, and Profit.
Leading companies such as Nike, Toyota, and Siemens are prioritizing sustainable innovation in their business models, setting an example for others to follow. In this Sustainability training presentation, you will learn key concepts, principles, and practices of sustainability applicable across industries. This training aims to create awareness and educate employees, senior executives, consultants, and other key stakeholders, including investors, policymakers, and supply chain partners, on the importance and implementation of sustainability.
LEARNING OBJECTIVES
1. Develop a comprehensive understanding of the fundamental principles and concepts that form the foundation of sustainability within corporate environments.
2. Explore the sustainability implementation model, focusing on effective measures and reporting strategies to track and communicate sustainability efforts.
3. Identify and define best practices and critical success factors essential for achieving sustainability goals within organizations.
CONTENTS
1. Introduction and Key Concepts of Sustainability
2. Principles and Practices of Sustainability
3. Measures and Reporting in Sustainability
4. Sustainability Implementation & Best Practices
To download the complete presentation, visit: https://www.oeconsulting.com.sg/training-presentations
Putting the SPARK into Virtual Training.pptxCynthia Clay
This 60-minute webinar, sponsored by Adobe, was delivered for the Training Mag Network. It explored the five elements of SPARK: Storytelling, Purpose, Action, Relationships, and Kudos. Knowing how to tell a well-structured story is key to building long-term memory. Stating a clear purpose that doesn't take away from the discovery learning process is critical. Ensuring that people move from theory to practical application is imperative. Creating strong social learning is the key to commitment and engagement. Validating and affirming participants' comments is the way to create a positive learning environment.
![Deleting a node in BST ,[object Object],[object Object],[object Object],http://ecomputernotes.com](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)